Okay, anything other than the degenerate case of a proc with no body?

proc{0} != proc{0}
proc{nil} != proc{nil}

I still contend that the documentation gives the mistaken impression 
that == can be used to compare the source code of the bodies of two procs.

	David

Nobuyoshi Nakada wrote:
> Hi,
> 
> At Tue, 5 Jun 2007 13:37:08 +0900,
> David Flanagan wrote in [ruby-core:11401]:
>> Can anyone construct two proc objects p1 and p2, without using clone or 
>> dup, so that p1==p2 but p1.object_id != p2.object_id?
> 
>   p proc{} == proc{}
> 
>> Based on this, I would think that:
>>
>>    lambda {|x| x*x } == lambda {|x| x*x }
>>
>> But this expression return false in both ruby 1.8 and 1.9.
> 
> Procs have each own contexts.
>